Answer to Question #4397 in Linear Algebra for Christina Butler
x/2 + y/3 = 2/3
x/2 + 2/y = -1
What is the solution of the system?
my school work is online. I can not copy and paste. How would you all be able to help me? There is a possibility of log back in & it being new question...
x/2 + y/3 = 2/3 x/2 + 2/y =-1
from the first equation we have x/2=2/3 - y/3. Substitute this into the second equation 2/y+2/3 -y/3=-1 2/y-y/3=-5/3 *3y: y^2-5y-6=0 (y-6)(y+1)=0 y_1=6; y_2=-1
Find the corresponding x=4/3-2y/3 x_1=4/3-2*6/3=-8/3 x_2=4/3-2*(-1)/3=2 Ans: (2,-1),(-8/3,6)