# Answer on Linear Algebra Question for Jacob Milne

Question #24293

Let A be an arbitrary M by N matrix and B the matrix in row-reduced echelon form obtained from A. Prove that there is a non-zero solution of the system of linear equations Ax = 0 iff B has fewer than N non-zero rows.

Expert's answer

As says Rouché–Capelli theorem, system of equations Ax=bhave a solution iff rank(A)=rank(A|b). Then we know that matrix A can be transformed into amatrix B in row-reduced echelon form using elementary row operations, each

operation is in one to one correspondence with left matrix multiplying by

elementary, and they are invertible, so matrix A and B are equivalent by

viewing that B=E

operation is in one to one correspondence with left matrix multiplying by

elementary, and they are invertible, so matrix A and B are equivalent by

viewing that B=E

_{1}E_{2}…E_{n}A, and E_{i}areelementary matrices. Thus systems Ax=0 and Bx=0 have the same solutions and by Rouché–Capelli theorem rank(B) = rank(A) =rank(A|0). If B has N non-zero rows, then N=rank(A) and A is invertible, so x=0. Then B has to have R fewer than Nnon-zero rows, then we canchoose N-R nonzero values of x components, and obtain the whole nonzero x.Need a fast expert's response?

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