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Answer to Question #16551 in Linear Algebra for Emerald Green
Question #16551
Solve by substitution or elimination:
[x+Y=13
[2x-3y=1
[x+Y=13
[2x-3y=1
Expert's answer
x+y=13 => y=13-x&
2x-3y=1
2x-3(13-x)=1
2x-39+3x=1
5x=40
x=8& => y=13-x=13-8=5
2x-3y=1
2x-3(13-x)=1
2x-39+3x=1
5x=40
x=8& => y=13-x=13-8=5
Learn more about our help with Assignments: Linear Algebra
Comments
x+y=13 2x-3y=1 x=13-y 2x-3y=1 x=13-y 2(13-y)-3y=1 x=13-y 26-2y-3y=1 x=13-y -5y=1-26 x=13-y 5y=25 x=13-y y=5 x=13-5=8 y=5 Answer is x=8,y=5 If anything is still unclear, please point out the step where you don't understand something.
how the answer was typed I am in Algebra 2 and my teacher doesn't teach it this way. I need this problem to be broken down a little bit more.
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