# Answer to Question #16551 in Linear Algebra for Emerald Green

Question #16551

Solve by substitution or elimination:

[x+Y=13

[2x-3y=1

[x+Y=13

[2x-3y=1

Expert's answer

x+y=13 => y=13-x&

2x-3y=1

2x-3(13-x)=1

2x-39+3x=1

5x=40

x=8& => y=13-x=13-8=5

2x-3y=1

2x-3(13-x)=1

2x-39+3x=1

5x=40

x=8& => y=13-x=13-8=5

Need a fast expert's response?

Submit orderand get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

## Comments

Assignment Expert17.10.12, 14:41x+y=13

2x-3y=1

x=13-y

2x-3y=1

x=13-y

2(13-y)-3y=1

x=13-y

26-2y-3y=1

x=13-y

-5y=1-26

x=13-y

5y=25

x=13-y

y=5

x=13-5=8

y=5

Answer is x=8,y=5

If anything is still unclear, please point out the step where you don't understand something.

Emerald Green17.10.12, 06:38how the answer was typed I am in Algebra 2 and my teacher doesn't teach it this way. I need this problem to be broken down a little bit more.

Assignment Expert16.10.12, 14:31Dear visitor

What is unclear to you? Please, give us the details so we could help you

Emerald Green15.10.12, 23:30I am confused with this answer.

## Leave a comment