Answer to Question #15753 in Linear Algebra for samy

Question #15753
3x-3y+z=1 -x+3y+2z=-4 x+3y+5z=-7 for the above system of linear equations find a solution and show that it has infinitely many solution or show that it has no soultion
Expert's answer
Let's find the determinant of the given system:

| 3 -3& 1 |
|-1& 3& 2 | = 3*3*5 + (-1)*3*1 + (-3)*2*1 - 1*3*1 - 3*2*3 - (-3)*(-1)*5 = 0.
| 1& 3& 5 |

The determinant of the given system is zero, so this system has infinitely many solutions.

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