Question #5587

slove dy/dx= x-e^x

Expert's answer

to solve this we rewrite it in the form dy=(x-e^x)dx

then we can integrate

both sides and we get

integral 1*dy=integral (x-e^x)dx

so y=0.5*x^2-e^x+C,

where C - constant is real number

then we can integrate

both sides and we get

integral 1*dy=integral (x-e^x)dx

so y=0.5*x^2-e^x+C,

where C - constant is real number

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