Answer to Question #45740 in Integral Calculus for victor

Question

Determine the following integral
∫x−3dx

Answer 1

∫(x−3)dx=∫(x−3)d(x-3)=|substitution t=x-3|=∫tdt=(t^2)/2+C=(x-3)^2/2+C, where C is an arbitrary real constant