Question #42375

Calculate fxxyz if f(x,y,z) = sin(3x+yz) .

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Question #42375, Math, Integral Calculus

Calculate fxxyz if f(x,y,z)=sin(3x+yz)f(x,y,z) = \sin(3x + yz).

Solution. f(x,y,z)=sin(3x+yz)f(x, y, z) = \sin(3x + yz)

fx(x,y,z)=3cos(3x+yz)f_x(x, y, z) = 3\cos(3x + yz)fxx(x,y,z)=9sin(3x+yz)f_{xx}(x, y, z) = -9\sin(3x + yz)fxxy(x,y,z)=9zcos(3x+yz)f_{xxy}(x, y, z) = -9z\cos(3x + yz)fxxyz(x,y,z)=9cos(3x+yz)+9yzsin(3x+yz).f_{xxyz}(x, y, z) = -9\cos(3x + yz) + 9yz\sin(3x + yz).


Answer. fxxyz(x,y,z)=9[yzsin(3x+yz)cos(3x+yz)]f_{xxyz}(x, y, z) = 9[yz\sin(3x + yz) - \cos(3x + yz)].


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