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Answer to Question #41147 in Integral Calculus for DEEPU SINGH

Question #41147
The surface f(x,y)=x2+y2 has a minimum at (0,0) .
Expert's answer
It is true, because x^2+y^2 is non-negative expression. So, the minimum of function f(x,y)=x^2+y^2 equals 0, when x=0 and y=0.

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