# Answer to Question #22516 in Integral Calculus for raepal

Question #22516

Find the derivative of

g(x)=∫[8x to 4x] (u+7)/(u-4) dx

B)))

Use part I of the Fundamental Theorem of Calculus to find the derivative of

h(x) = ∫[sin(x) to -3] (cos(t^3)+t)dt

C)))

F(x) = ∫[ 1 to √3] s^3/(3+5s^4) dx

g(x)=∫[8x to 4x] (u+7)/(u-4) dx

B)))

Use part I of the Fundamental Theorem of Calculus to find the derivative of

h(x) = ∫[sin(x) to -3] (cos(t^3)+t)dt

C)))

F(x) = ∫[ 1 to √3] s^3/(3+5s^4) dx

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