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Answer to Question #16165 in Integral Calculus for diey

Question #16165
∫∫∫2y2z dxdzdy ?
∫∫∫dzdxdy ?
Expert's answer
∫∫∫2y2z dxdzdy =∫∫(∫2y2z dx)dzdy=∫∫ (4yz*x+c1) dzdy=∫ (∫ (4yx*z+c1) dz) dy=∫

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