Question #4700

determine the x intercepts of the function:
f(x) = x^2 -8x -18

Expert's answer

Let's consider the following equation:

x^2 - 8x – 18 = 0.

Let's find the discriminant of a given square equation:

D = 8^2 - 4*(-18) = 136 = 4*34, so sqrt(D) = 2sqrt(34).

Let's write down the solution of a given equation using standard formulas for solution of a square equation:

x1 = (8 + 2sqrt(34))/2 = 4 + sqrt(34);

x2 = (8 - 2sqrt(34))/2 = 4 - sqrt(34).

So, the x intercepts of the function are x1 = 4 + sqrt(34) and x2 = 4 - sqrt(34).

x^2 - 8x – 18 = 0.

Let's find the discriminant of a given square equation:

D = 8^2 - 4*(-18) = 136 = 4*34, so sqrt(D) = 2sqrt(34).

Let's write down the solution of a given equation using standard formulas for solution of a square equation:

x1 = (8 + 2sqrt(34))/2 = 4 + sqrt(34);

x2 = (8 - 2sqrt(34))/2 = 4 - sqrt(34).

So, the x intercepts of the function are x1 = 4 + sqrt(34) and x2 = 4 - sqrt(34).

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