Question #73356

Find the equilibrium of L and K subject to a given output:

minimize cost: C=40K+20L subject to Q=60LK = 3000

minimize cost: C=40K+20L subject to Q=60LK = 3000

Expert's answer

C=40K+20L subject to Q=60LK = 3000

Q=60LK = 3000 , LK =50, then C = 40K + 20L = 40*5 + 20*10=400, L = 10, K=5

Q=60LK = 3000 , LK =50, then C = 40K + 20L = 40*5 + 20*10=400, L = 10, K=5

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## Comments

Shahid Abbas14.03.19, 13:00Can someone kindly explain the below concept further please C=40K+20L subject to Q=60LK = 3000 Q=60LK = 3000 , LK =50, then C = 40K + 20L = 40*5 + 20*10=400, L = 10, K=5

Assignment Expert25.01.19, 18:43Dear Sultan, To find minimum for Cost we need to solve equation like dC/dK=0 with respect to L=K/50. It will give as the answer K=5. Then L=10

Sultan25.01.19, 12:33Please explain from where the 5 and 10 came from plz tell answer in details 40*5 + 20*10=400, L = 10, K=5

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