Answer to Question #68115 in Microeconomics for aina
Q = 10X + 4Y + 0.2XY
Where Q = number of treated of fence post produced per day
X = machine hours of cutting and shaping machinery used per day
Y = labor hours used per day
Px = RM250 per unit
Py = RM100 per unit
When the daily operating budget is RM1500, determine the maximum number of treated fence posts that can be produced per day. Also, specify the optimal number of labor hours and machine hours used each day.
1) MCx/ MCY = PX/PY, (10+0.2Y)/(4+0.2X) = 2.5, then 10+0.2Y = 10+0.5X, Y=2.5X
2) 1500 = 250X + 250X, where Y = 2.5X, X = 3, Y = 7.5, Q = 64.5.
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