Maximizing profits from cost function of C=50 + 4Q^2 with price of $40
Let P(q) be the profit function, P (q) =q*p (q)-C (q) =q*40-(50+4q^2) =-4q^2+40q-50 To maximize the profit function, take its first derivative and set equal to zero. dP/dq=0 dP/dq (-4q^2+40q-50)=0 -8*q+40=0 q=5 The maximum profit is P (5) .
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