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Answer to Question #51129 in Microeconomics for Paul Muchira

Question #51129
Question 1
Mr. Hassan’s demand function for rice is given by
X = 15 + M (10P) -1
Where X = amount of rice demanded, M = income of the consumer, P = price of rice.
Originally, the income of Mr. Hassan is \$ 4,800 per month and the price of rice is \$120/kg. If the price falls to \$ 100/kg, calculate to total effect (TE), substitution effect (SE) and Income effect (IE) emanating from this change in price.
Question 2
(a) Given the following monotonically transformed utility function faced by the consumer
U(X1X2) = X_1^0.5 X_2^0.5
The price of good X1 is P1 and the price of good X2 is P2. Derive the optimal demand (Marshallian demand) function for X1 and for X2.
Question 3
Under a perfect competition the price as sh. 6 per unit has been determined. An individual firm has a total cost function given by C=10+15Q - 5Q^2+Q^3/3. Find:
i) Revenue function
ii)The quantity produced at which profit will be maximum profit
iii)Maximum profit
Question 1
Mr. Hassan&rsquo;s demand function for rice is given by
X = 15 + M (10P)^-1
M = \$ 4,800 per month, P = \$120/kg.
If the price falls to \$ 100/kg:
1) the total effect TE = X2 - X1 = 15 + 4800/(10*120) - 15 - 4800/(10*150) = 0.8 kg
2) substitution effect SE = Xh - X0 = 15 + (4800*150/120)/(10*150) - 15 - 4800/(10*120) = 0 kg
3) income effect IE = X1 - Xh = 15 + 4800/(10*150) - 15 - (4800*150/120)/(10*120) = 0.8 kg
Question 2
(a) U(X1X2) = X1^0.5 X2^0.5
The price of good X1 is P1 and the price of good X2 is P2.
Optimal demand (Marshallian demand) function for X1 and for X2 will be:
X = (0.5I/P1, 0.5I/P2)
Question 3
P = 6 per unit
C=10+15Q - 5Q^2+Q^3/3.
i) Revenue function is:
TR = P*Q = 6Q
ii) The quantity produced at which profit will be maximum profit is in the point, where marginal revenue equals marginal cost: MR = MC
MR = TR&#039; = 6
MC = C&#039; = 15 - 10Q + Q^2
15 - 10Q + Q^2 = 6
Q^2 - 10Q + 9 = 0
Q1 = 9 units, Q2 = 1 unit (may not be profit maximizing).
iii) Maximum profit is:
TP1 = TR - TC = 6*1 - (10+15-5+1/3) = -\$14.33
TP2 = TR - TC = 6*9 - (10 + 15*9 - 5*81 + 729/3) = 54 - 17 = \$37

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