Question #30870

a salesman know to sell a product in 3 out of 5 attempts while another salesman in 3 out of 4 attempts when they both try to sell the product find the probability .
1.no sale will be effected
2.both of them will sell the product

Expert's answer

A represents the event that the first salesman is able to sell the product.

A^c represents the event that the first salesman is not able to sell the product.

B represents the event that the second salesman is able to sell the product.

B^c represents the event that the second salesman is not able to sell the product.

It is given that

P(A)=3/5 and P(B)=2/5

Therefore,

P(A^c )=1- 3/5=2/5 and P(B^c )=1-2/5=3/5

The required probabilities are calculated as follows:

P ( no sale will be affected when they both try to sell the product)

= P(A^c B^c )= P(A^c ) P (B^c) (By multiplication theorem)

=2/5*3/5

=6/25

= 0.24

A^c represents the event that the first salesman is not able to sell the product.

B represents the event that the second salesman is able to sell the product.

B^c represents the event that the second salesman is not able to sell the product.

It is given that

P(A)=3/5 and P(B)=2/5

Therefore,

P(A^c )=1- 3/5=2/5 and P(B^c )=1-2/5=3/5

The required probabilities are calculated as follows:

P ( no sale will be affected when they both try to sell the product)

= P(A^c B^c )= P(A^c ) P (B^c) (By multiplication theorem)

=2/5*3/5

=6/25

= 0.24

## Comments

## Leave a comment