What is the molality of a solution containing 11.7 g Na 2 SO 4 dissolved in 2383.6 g of water?
Сm = n / m
n = m / M
M (Na2SO4) = 142.04 g/mol
n (Na2SO4) = 11.7 / 142.04 = 0.08 mol
Cm (Na2SO4) = 0.08 / 2.3836 = 0.03 m
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment