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Answer to Question #33908 in C++ for deepsy lata

Question #33908
Use a one-dimensional array to solve the following problem. A company pays its salespeople on a commission basis. The salespeople each receive \$200 per week plus 9 percent of their gross sales for that week. For example, a salesperson who grosses \$5000 in sales in a week receives \$200 plus 9 percent of \$5000, or a total of \$650. Write a program (using an array of counters) that determines how many of the salespeople earned salaries in each of the following ranges (assume that each salesperson&rsquo;s salary is truncated to an integer amount); a) \$200-299 b) \$300-399 c) \$400-499 d) \$500-599 e) \$600-699 f) \$700-799 g) \$800-899 h) \$900-999 i) \$1000 and over
1
2013-08-16T09:40:08-0400
#include <iostream>
#include <cstdio>

using namespace std;

/* A number of salespeople in the company */
static const int SALESPERSON_COUNT = 25;

int main()
{
/* An array of salespeople earned salaries */
int salaries[SALESPERSON_COUNT] = { 204, 733, 806, 967, 262,
1075, 1060, 1072, 255, 462,
995, 564, 886, 924, 201,
884, 938, 1033, 264, 1026,
215, 238, 348, 644, 563};
/* An array of counters showing how many salesperson salaries
* are in each of the nine ranges */
int counters[9] = {0};
int index;

for (int k = 0; k < SALESPERSON_COUNT; k++)
{
index = (salaries[k] - 200) / 100;//get counter index for a salary range
counters[index]++;
}

/* Output salary list */
cout << "Salespeople earned salaries:" << endl;
for (int k = 0; k < SALESPERSON_COUNT; k++)
cout << " " << salaries[k];
cout << endl << endl;

/* Display the array of counters */
char buf[64];
for (int z = 0; z < 8; z++)
{
sprintf(buf, " %c) \$%d-%d: ", 'a' + z, 200 + z * 100, 299 + z * 100);
cout << buf << counters[z] << endl;
}
cout << " i) \$1000 < " << counters[8];
return 0;
}

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