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Answer to Question #16935 in C++ for Bishoy fam

Question #16935
Write an algorithm that determines the day number ( 1 to 366) in a year for a date that is provided as input data. For example, 1/1/1994 is the day number 1, while, 31/12/1994 is the day number 366 because 1994 is a leap year.

Hint: A year is a leap year if it is devisable by 4 except any year that is divisible by 100 is a leap year if it is divisible by 400.
( sorry i want it in flowchart and pseudo-code)
Expert's answer
#include<iostream>
using namespace std;

char msg[200], inv[200];
int y, m, d, n=0, i;

void main(){
cout<<"enter the year: ";
cin>>y;
cout<<"enter the month: ";
cin>>m;
cout<<"enter the day: ";
cin>>d;
n += d;
for (i=1; i<m; i++){
& if (i==1) n+=31;
& if ((y%4==0)&&(i==2)) n+=29;
& else if (i==2) n+=28;
& if (i==3) n+=31;
& if (i==4) n+=30;
& if (i==5) n+=31;
& if (i==6) n+=30;
& if (i==7) n+=31;
& if (i==8) n+=31;
& if (i==9) n+=30;
& if (i==10) n+=31;
& if (i==11) n+=30;
}
cout<<"the day number is "<<n<<".\n";
}

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