Answer to Question #94679 in Quantum Mechanics for Mosin Hafeez

Question #94679
light quanta of energy 3.5*10^-19J falls on cathode of phto cell the current through cell is reduced to zero by applying potential difference of 0.25Vwhat is work function of cathode
1
Expert's answer
2019-09-18T09:51:15-0400

The energy of quanta will be enough to perform work of ejecting electrons from the surface of the metal and to stop the current:


"h\\nu=A+E_{p.d},\\\\\nA=h\\nu-E_{p.d.}=h\\nu-e\\phi=\\\\\n=3.5\\cdot10^{-19}-1.6\\cdot10^{-19}\\cdot0.25=\\\\\n=3.099\\cdot10^{-19}\\text{ J}."

Seems like caesium was used as a material for the cathode.


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