# Answer to Question #74122 in Other Physics for Cesar

Question #74122

What is the momentum of a 50 kg skydiver who falls for 2 seconds?

Expert's answer

The momentum p of an object of mass m and velocity v is defined according to the following relationship:

p=mv

The velocity of any free falling object at any time is

v=at

The acceleration is constant and equal to the gravitational acceleration g which is 9.8 meters per square second at sea level on the Earth.

So,

p=mgt=(50 kg)(9.8 m/s^2 )(2 s)=980 kg m/s

p=mv

The velocity of any free falling object at any time is

v=at

The acceleration is constant and equal to the gravitational acceleration g which is 9.8 meters per square second at sea level on the Earth.

So,

p=mgt=(50 kg)(9.8 m/s^2 )(2 s)=980 kg m/s

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