Answer to Question #70659 in Other Physics for zamar
A 20g mass is suspended from a metre rod at the 20cm.The metre rod is balanced on 40cm mark on wedge.Weight of metre rod is?
The pivot point is at the 40 cm mark. The weight of the 20 gram object is at the 20 cm mark. Counter clockwise torque: 0.02(10)(0.4-0.2) =0.04 The weight of the rod is at the center of the rod. Clockwise torque: W(0.5-0.4)=0.1W The weight of meter rod is W=0.04/0.1=0.4 N.