Answer to Question #70659 in Other Physics for zamar

Question #70659
A 20g mass is suspended from a metre rod at the 20cm.The metre rod is balanced on 40cm mark on wedge.Weight of metre rod is?
Expert's answer
The pivot point is at the 40 cm mark. The weight of the 20 gram object is at the 20 cm mark.
Counter clockwise torque:
0.02(10)(0.4-0.2) =0.04
The weight of the rod is at the center of the rod.
Clockwise torque:
W(0.5-0.4)=0.1W
The weight of meter rod is
W=0.04/0.1=0.4 N.

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be first!

Leave a comment

Ask Your question

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS
paypal