Answer to Question #61694 in Physics for DEVENDRA SINGH

Question #61694
A ball of mass m
1 = 8.0 × 10−2 kg starts from rest and falls vertically downward from a
height of 3.0 m. After colliding with the ground, it bounces up to a height of 2.0 m. The
collision takes place over a time interval of t = 5.0 ×10−3 s. Calculate (i) the
momentum of the ball immediately before and immediately after the collision,
(ii) average force exerted by the ground on the ball and (iii) impulse imparted to the
ball?
1
Expert's answer
2016-09-07T14:01:13-0400
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