# Answer to Question #54175 in Other Physics for kate

Question #54175

A recovery vehicle is towing a broken down lorry, of mass 42 tonne, up an incline of 1 in 10. Both vehicles start from rest and accelerate constantly up the incline at 0.1m/s2. If the resistance to motion (not the gravitational component) is:-

F = 820 + 0.06V3 where F is resistance in Newtons and V is velocity in m/s. What is power in kW transmitted through the tow hook to the lorry at a velocity of 10m/s?

A. 462.82 B. 556.34 C. 67.65 D. 120.8 E. 1220.67

F = 820 + 0.06V3 where F is resistance in Newtons and V is velocity in m/s. What is power in kW transmitted through the tow hook to the lorry at a velocity of 10m/s?

A. 462.82 B. 556.34 C. 67.65 D. 120.8 E. 1220.67

Expert's answer

Need a fast expert's response?

Submit orderand get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

## Comments

## Leave a comment