84 739
Assignments Done
99%
Successfully Done
In March 2020

# Answer to Question #28033 in Other Physics for tucki

Question #28033
On Earth&#039;s surface, we are about 6,500 km from Earth&#039;s center. The force of gravity on a certain person, at Earth&#039;s surface, causes his weight to be 160 lbs. How much will the person weigh at a distance of 13,000 km from Earth&#039;s center?
1
2015-05-28T07:05:44-0400
g=G*M/R^2 - General formula to acceleration of gravity
G- gravity constant, R - distance, M Earth mass, in this problem G*M - const
P(weight of body)=m*g with this force body act to the Earth (weight isn&#039;t mass, it&#039;s depends from g)
P1=m*g1=160lbs Count weight of body for first case (from condition)
g1=const/(6,500*10^3)^2 cause g from first distance from the center
g2=const/(13,000*10^3)^2 from the second distance
note 6,500*10^3 as L (for convenience)
g1=const/L^2 &
g2=const/(2L)^2 rewrite equations
so g1=4*g2 (from two previous equations)
P2=mg2=(mg1)/4=40 lbs& (express g2 from g1 and substitute into equetion)
Answer weight of person at a distance of 13,000 km from Earth&#039;s center = 40 lbs

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!