Question #69943

When 24.7 cal of heat is added to 18.8 g of aluminum at 22.0 âˆ˜C, what is the final temperature of the aluminum?

Expert's answer

Q=Câˆ™mâˆ™âˆ†T

Specific heat capacity of Aluminum:C= 920 J/(kgâˆ™â„ƒ)

1 cal=4.187 J,

24.7-x J; x=24.7âˆ™4.187=103.42 J

103.42 J=920 J/(kgâˆ™â„ƒ)âˆ™0.0188 kgâˆ™âˆ†T

âˆ†T=103.42/(920âˆ™0.0188)=6â„ƒ

âˆ†T=T_2-T_1,where T_2=âˆ†T+T_1=6+22=28â„ƒ.

Answer: 28â„ƒ.

Specific heat capacity of Aluminum:C= 920 J/(kgâˆ™â„ƒ)

1 cal=4.187 J,

24.7-x J; x=24.7âˆ™4.187=103.42 J

103.42 J=920 J/(kgâˆ™â„ƒ)âˆ™0.0188 kgâˆ™âˆ†T

âˆ†T=103.42/(920âˆ™0.0188)=6â„ƒ

âˆ†T=T_2-T_1,where T_2=âˆ†T+T_1=6+22=28â„ƒ.

Answer: 28â„ƒ.

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