# Answer to Question #69943 in Molecular Physics | Thermodynamics for Teresa

Question #69943

When 24.7 cal of heat is added to 18.8 g of aluminum at 22.0 ∘C, what is the final temperature of the aluminum?

Expert's answer

Q=C∙m∙∆T

Specific heat capacity of Aluminum:C= 920 J/(kg∙℃)

1 cal=4.187 J,

24.7-x J; x=24.7∙4.187=103.42 J

103.42 J=920 J/(kg∙℃)∙0.0188 kg∙∆T

∆T=103.42/(920∙0.0188)=6℃

∆T=T_2-T_1,where T_2=∆T+T_1=6+22=28℃.

Answer: 28℃.

Specific heat capacity of Aluminum:C= 920 J/(kg∙℃)

1 cal=4.187 J,

24.7-x J; x=24.7∙4.187=103.42 J

103.42 J=920 J/(kg∙℃)∙0.0188 kg∙∆T

∆T=103.42/(920∙0.0188)=6℃

∆T=T_2-T_1,where T_2=∆T+T_1=6+22=28℃.

Answer: 28℃.

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