Each of three identical bodies has a temperature-independent heat capacity C. The three bodies have initial temperatures T3>T2>T1. What is the maximum amount of work that can be extracted leaving the three bodies at a common final temperature?
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Expert's answer
2011-11-04T12:20:42-0400
final temperature of the three bodies would be (T1+T2+T3)/3 = T1 (say) work done in heat exchange by the three bodies = mc[(T1-T1)+(T1-T2)+(T1-T3)] = 2mc(T1+T2+T3)/3
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