Answer to Question #39780 in Molecular Physics | Thermodynamics for rupesh kumar
4.18X10^3 JKg^-1K^-1 and latent heat of vaporisation is 2.24x10^6 JKg^-1.
b) Calculate the work done by one mole of a van der Waals’ gas if during its isothermal
expansion its volume increases from 1m^3 to 2m^3 at a temperature 300K.
Take a = 1.39X10^-6 atm m^6 mol^-2 and b = 39.1X10^-6 m^3 mol^-1.
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