Question #343335

A scuba driver is in fresh water has a tank with a volume of 0.0100m^3. The air in the tank is initially at a pressure of 1.00×10^7 Pa. Assume that the driver breathes 0.500 L/s of air. Density of fresh water is 1.00×10^3 kg/m^3.

How long will it take the tank at depths of 2.70 m?

Expert's answer

"V_2=V_1\\frac{p_1}{p_0+\\rho gh}=0.78~m^3,"

"t=\\frac Vv=26~min."

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