Question #17059

A juggler throws a ball with an initial horizontal velocity of +1.1 m/s and an initial vertical velocity of +5.7 m/s. What is its
acceleration at the top of its flight path? Make sure to consider the sign when responding. Consider the upward direction as positive.

Expert's answer

The acceleration remains constant during all time of flight of the ball

and equals to -g = -9.8 m/s2 (downward)& if we assume the upward

direction as positive.

and equals to -g = -9.8 m/s2 (downward)& if we assume the upward

direction as positive.

## Comments

## Leave a comment