Answer to Question #889 in Mechanics | Relativity for Rooky
A 6 kg cart on a level surface is pulled at a constant velocity of 2 m/sec by a constant force of 10 N. What is the acceleration? What is the friction force opposing the motion?
show work (so i know how to do it) and answer please
As the car is pulled at a constant velocity, the acceleration and vector sum of the forces acting on the car equals to zero.
Thus a = 0;
F - Ffrict = 0;
Ffrict = 10 N.