# Answer to Question #889 in Mechanics | Relativity for Rooky

Question #889

A 6 kg cart on a level surface is pulled at a constant velocity of 2 m/sec by a constant force of 10 N. What is the acceleration? What is the friction force opposing the motion?

show work (so i know how to do it) and answer please

show work (so i know how to do it) and answer please

Expert's answer

As the car is pulled at a constant velocity, the acceleration and vector sum of the forces acting on the car equals to zero.

Thus a = 0;

F - F

F

Thus a = 0;

F - F

_{frict}= 0;F

_{frict}= 10 N.Need a fast expert's response?

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