Answer to Question #7710 in Mechanics | Relativity for david peplow
Calculate the acceleration of a body of mass 79 kg that has a force of 916 N acting on it at an angle of 29 degrees to the horizontal.
The gravity force acting on a body is
G = mg = 79*9.8 = 774.2 N.
The horizontal component of a net force acting on a body is
Fh = 916*cos29 = 801.1517 N
The vertical component of a net force acting on a body is
Fv = 916*sin29 - mg = 916*sin29 - 79*9.8 = -330.1144 N.
The net force is
Fn = √(Fh²+Fv²) = √(801.1517²+330.1144²) = 8.6650 N.
So, according to the second Newton's law, the acceleration of a body is
a = Fn/m = 8.6650/79 = 0.1097 m/s².