Question #726

The distance between two telephone poles is
49 m. When a 1.35 kg bird lands on the
telephone wire midway between the poles, the
wire sags 0.185 m.
The acceleration of gravity is 9.8 m/s2 .
How much tension in the wire does the bird
produce? Ignore the weight of the wire.
Answer in units of N.

Expert's answer

T1 | T2 | m*g=0 ⇒ 2*T1*sin (C) =mg ⇒

⇒ T2=T1=mg/(2*AB/AC) = mg/(2*0.185/ √(24.5² + 0.185²)) = 876H

⇒ T2=T1=mg/(2*AB/AC) = mg/(2*0.185/ √(24.5² + 0.185²)) = 876H

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