Answer to Question #726 in Mechanics | Relativity for Brian

Question #726
The distance between two telephone poles is 49 m. When a 1.35 kg bird lands on the telephone wire midway between the poles, the wire sags 0.185 m. The acceleration of gravity is 9.8 m/s2 . How much tension in the wire does the bird produce? Ignore the weight of the wire. Answer in units of N.
1
Expert's answer
2010-10-05T10:08:29-0400
T1 | T2 | m*g=0 ⇒ 2*T1*sin (C) =mg ⇒
⇒ T2=T1=mg/(2*AB/AC) = mg/(2*0.185/ √(24.5² + 0.185²)) = 876H

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