Answer to Question #72323 in Mechanics | Relativity for atique
If Phosphorous is doped with silicon and silicon is doped with Boron, identified the type of
Outermost electron of Phosphorous is 5 and outermost electron of silicon is 4. so phosphorous is doped with silicon, then 4 electrons of phosphorous is bonded with four silicon, and one electron will be left unbonded. So we will get free electrons, hence it will be n-types.
Again silicon has 4 outermost electrons and boron has 3. If silicon is doped with Boron, same way we get one extra electron per silicon dopped atom, so it will be again n-types,