Answer to Question #6413 in Mechanics | Relativity for parth
F1 = mg/sinα - the gravity force (here sinα = 2m/12m = 1/6);
F2 = 100N - pulling force;
F3 - unknown friction force.
Now let's write down the second Newton's law:
F1 + F2 - F3 = ma.
Let's guess what acceleration a is equal to.
S = V*t/2 ==> t = 2*S/V = 2*12/2 = 12 s (the moving time).
We know that
S = a*t²/2 ==> a = 2*S/t² = 2*12/12² = 2/12 = 1/6 m/s.
F3 = F1 + F2 - ma = mg/sinα + 100 - ma = 50*9.8/6 + 100 - 50/6 = 520/3 = 173.(3) N.
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