# Answer to Question #54176 in Mechanics | Relativity for kate

Question #54176

A recovery vehicle is towing a broken down lorry, of mass 42 tonne, up an incline of 1 in 10. Both vehicles start from rest and accelerate constantly up the incline at 0.1m/s2. If the resistance to motion (not the gravitational component) is:-

F = 820 + 0.06V3 where F is resistance in Newtons and V is velocity in m/s. What is power in kW transmitted through the tow hook to the lorry at a velocity of 10m/s?

A. 462.82 B. 556.34 C. 67.65 D. 120.8 E. 1220.67

F = 820 + 0.06V3 where F is resistance in Newtons and V is velocity in m/s. What is power in kW transmitted through the tow hook to the lorry at a velocity of 10m/s?

A. 462.82 B. 556.34 C. 67.65 D. 120.8 E. 1220.67

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