Question #5334

In the spin cycle of a washing machine, the tub of radius 0.44 m rotates at a constant rate of 705 rev/min. What is the centrifugal forcess acts on clothes having capacity 7 Kg.Answer in units of N.

Expert's answer

Let's make some denotations:

R = 0.44 m;

M = 7 kg;

N = 705 rev/min.

The liniar velocity of a point at the tub is

V = N*2*R*pi = 705*2*0.44*3.14 = 1948.056 m/min = 32.4676 m/s.

Centripetal acceleration:

Ac = V²/R = 32.4676²/0.44 = 2395.784204 m/s².

So, centrifugal force is

F = M*Ac = 7*2395.784204 = 16770.489428 N.

R = 0.44 m;

M = 7 kg;

N = 705 rev/min.

The liniar velocity of a point at the tub is

V = N*2*R*pi = 705*2*0.44*3.14 = 1948.056 m/min = 32.4676 m/s.

Centripetal acceleration:

Ac = V²/R = 32.4676²/0.44 = 2395.784204 m/s².

So, centrifugal force is

F = M*Ac = 7*2395.784204 = 16770.489428 N.

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