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# Answer to Question #5326 in Mechanics | Relativity for sharif ibrahim

Question #5326
A 100g stone is thrown straight upwards at 19 m/s from the top of a 75 m building.

(a) What is the Stone&#039;s velocity as it hits the ground?
(b) What is the maximum height of the stone?
(c)What is the stone&#039;s kinetic energy when the gravitational potential energy is 30% less than when it started?
(d) What is the stone&#039;s gravitational potential energy 1.0 s before it touches the ground?
m=100 kg
h=75m
v0=19m/s
a) When the stone hits the ground its the gravitational potential energy is equal zero, so lets use the law of energy conservation:

b) The maximum height of the stone is achieved when the stones kinetic energy is equal zero. So lets use the law of energy conservation:

c) Let`s use the law of energy conservation:

d) We need use the time of the fall

a) 42.8 m/s
b) 93.4 m
c) 40.1 kj
d) 39.2 kj

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