# Answer to Question #52485 in Mechanics | Relativity for Helen

Question #52485

A car driving at 35.0 m/s takes 26 minutes to travel a certain distance according to the drivers clock in the car. How long does the trip take according to an observer at rest on Earth?

Expert's answer

Solution:

Given:

v=35 m/s

t = 26 min = 26*60 = 1560 s

Needs to find t'-?

Solution:

t'=t/sqrt(1- (v/c)^2)

Calculation in MATLAB

>> format long

>> 1560/sqrt(1 - (35/299792458)^2)

ans =

1.560000000000011e+03

>> 1560/sqrt(1 - (35/299792458)^2)

ans =

1.560000000000011e+03

>> 1560/sqrt(1 - (35/299792458)^2) - 1560

ans =

1.068656274583191e-11

Answer is 1.068656274583191e-11

Given:

v=35 m/s

t = 26 min = 26*60 = 1560 s

Needs to find t'-?

Solution:

t'=t/sqrt(1- (v/c)^2)

Calculation in MATLAB

>> format long

>> 1560/sqrt(1 - (35/299792458)^2)

ans =

1.560000000000011e+03

>> 1560/sqrt(1 - (35/299792458)^2)

ans =

1.560000000000011e+03

>> 1560/sqrt(1 - (35/299792458)^2) - 1560

ans =

1.068656274583191e-11

Answer is 1.068656274583191e-11

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