Answer to Question #4191 in Mechanics | Relativity for Nantu
Question #4191
Consider a ball of mass m1 moving with a velocity u1 collides elastically with a ball of mass m2 at rest.Show that the maximum energy transfer takes place when m1=m2.
Expert's answer
The Energy transfer equation is
W=E2 - E1=m (u12)/2 - 0 = m (u12)/2.
The Momentum conservation law
m1u1 = m2u2+m1 u1'.
Thus, when masses are equal, the second ball begins to move with the speed u2=u1 - u1' .
W=E2 - E1=m (u12)/2 - 0 = m (u12)/2.
The Momentum conservation law
m1u1 = m2u2+m1 u1'.
Thus, when masses are equal, the second ball begins to move with the speed u2=u1 - u1' .
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Thank you very much for the above work it was exactly what i wanted, I will use this service again
#207209 on Jun 2018
#207209 on Jun 2018 
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