# Answer to Question #4191 in Mechanics | Relativity for Nantu

Question #4191

Consider a ball of mass m1 moving with a velocity u1 collides elastically with a ball of mass m2 at rest.Show that the maximum energy transfer takes place when m1=m2.

Expert's answer

The Energy transfer equation is

W=E

The Momentum conservation law

m

Thus, when masses are equal, the second ball begins to move with the speed u

W=E

_{2 }- E_{1}=m (u_{1}^{2})/2 - 0 = m (u_{1}^{2})/2.The Momentum conservation law

m

_{1}u_{1 }= m_{2}u_{2}+m_{1}u_{1}'.Thus, when masses are equal, the second ball begins to move with the speed u

_{2}=u_{1 }- u_{1}' .Need a fast expert's response?

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