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Answer to Question #3847 in Mechanics | Relativity for mia

Question #3847
As everyone knows, bullets bounce from Superman’s chest. Suppose Superman, mass
104 kg, while not moving, is struck by a 4.2 g bullet moving with a speed of 835 m/s. If the
collision is elastic, find the speed that Superman had after the collision. (Assume the
bottoms of his superfeet are frictionless.)
Expert's answer
Let m1 be the mass of the bullet (m1 = 4.2 g), m2 - the mass of Superman (m2 = 104 kg), .U - speed of the bullet before the colision,
V - speed of Superman after the collision.
Consider that the bullet stopped after the collision.
According to the law of conservation of linear momentum:

m1U = m2VV = U*m1/m2V = 835*0.0042/104 = 0.0337 m/s

So, the speed of Superman is 0.0337 m/s.

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