Answer on Mechanics | Relativity Question for cesarpintor
S - cross sectional area; h-height of the cylinderthen volume of displaced water is V1=2/3*S*h; The weight of the displaced water
volume V1 is P=ρgV1, where ρ - density of water, g - gravitational acceleration.
So, P=2/3*ρgSh; P=2/3*1000*10*20*10^(-4)*0.9=12 (N)
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