Answer to Question #26121 in Mechanics | Relativity for cesarpintor
A solid cylinder of wood has a cross sectional area of 20cm2 and height of 90cm. It floats upright in water. If two thirds of the length of the cylinder is submerged, calculate: the weight of the water displaced?
According to the condition, volume of displaced waterequals 2/3 of cylinder's volume. We can easily find cylinder's volume: V=S*h, S - cross sectional area; h-height of the cylinderthen volume of displaced water is V1=2/3*S*h; The weight of the displaced water volume V1 is P=ρgV1, where ρ - density of water, g - gravitational acceleration. So, P=2/3*ρgSh; P=2/3*1000*10*20*10^(-4)*0.9=12 (N)