Answer to Question #20776 in Mechanics | Relativity for Christa
A) what is the horizontal range of the arrow?
B) what is the maximum height of the arrow?
Hence, if flight will last time t, the equation for vertivalvelocity is
2v(vert.)=gt, t =2v/g = 50/9.8 = 5.1 sec
A. horizontal range is
v(hor.)*t = 50*cos(30)*5.1 = 220 m
B.Height of arrow is
h=v(vert)^2 / (2g) = 31.8 m
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