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Answer to Question #18436 in Mechanics | Relativity for uyange18

Question #18436
Two parallel and opposite forces, each 4,000 N are applied tangentially to the upper
and lower faces of a cubical metal block 25 cm on a side. Find the angle of shear and
the displacement of the upper surface relative to the lower surface. Shear modulus for
the metal is 80 GPa.
Expert's answer
Tan Q =(25×10 ̄ 7/ 25× 10 ̄ 2) = 8.0 × 10 ̄ 7 rad.
Displament = 4000 / (2.8 × 10 ̄ ²)²
80 Gpa = 64000 / Ʃ
Ʃ = 64000 / 80 G
= 80 × 10 ̄ 7 (25 × 10 ̄ ² )
= 2 × 10 ̄ 7.

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