Question #17623

A person walks 49 m East and then walks 30 m at an angle 49 degrees North of East.

What is the magnitude of the total displacement?

What is the magnitude of the total displacement?

Expert's answer

According to the law of cosines:

a = √(b² + c² - 2*b*c*cos(α)) = √(49² + 30² - 2*49*30*cos(180° - 49°)) = 72.317 m.

a = √(b² + c² - 2*b*c*cos(α)) = √(49² + 30² - 2*49*30*cos(180° - 49°)) = 72.317 m.

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