Answer to Question #17119 in Mechanics | Relativity for Aditya N Pai
a lift whose cage is 3m high is moving up with an acceleration of 2m/s.a piece of stone is dropped from the top of the cage of the lift when its velocity is 8m/s.if g=10m/s square ,then the stone will reach the floor of the lift after
h = V0 * t + (a + g) * t^2 / 2 3 = 8 * t + (2 + 10) * t^2 / 2 6 * t^2 + 8 * t - 3 = 0 t = 0.3052 s
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