Answer to Question #16632 in Mechanics | Relativity for dellashantae
m*g = k*Δl ==> k = m*g/ΔL = 12[kg]*9.8[m/s²]/0.0012[m] = 98000 [kg/s²].
M*g = k*ΔL ==> ΔL = M*g/k = 175[kg]*9.8[m/s²]/98000[kg/s²] = 0.0175 m.
So, the elongation of the spring will be 1.75 cm.
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