# Answer to Question #15474 in Mechanics | Relativity for Siti zahidah

Question #15474

A motorist travelling at 72km/h on a straight road approaches a traffic light which turn red when he is 55m away from the stop line.The reaction time is 0.7s.With the brakes applied fully,the vehicle decelerates at 5m/s^2.How far from the stop line will he stop and on which side of the stop line?

Expert's answer

It will take him

T = 72[km/h]/5[m/s²] = 0.7[s] + 72*1000/3600[m/s]/5[m/s²] = 4 s

to come to a complete stop after applying the brakes.

He'll go

L = (0.7[s] + 4[s]/2)*72*1000/3600[m/s] ≈ 54 m

before coming to a stop. So, he'll stop 55[m] - 54[m] = 1 meter before the stop line.

T = 72[km/h]/5[m/s²] = 0.7[s] + 72*1000/3600[m/s]/5[m/s²] = 4 s

to come to a complete stop after applying the brakes.

He'll go

L = (0.7[s] + 4[s]/2)*72*1000/3600[m/s] ≈ 54 m

before coming to a stop. So, he'll stop 55[m] - 54[m] = 1 meter before the stop line.

Need a fast expert's response?

Submit orderand get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

## Comments

Assignment Expert27.08.14, 19:10The path is

L = v*t0 + a*t^2/2

where v = 72 kmph is the initial velocity, a = 5 m/s^2 is the deceleration, t is time of decelerated motion and t0 = 0.7 s is a reaction time. We know that a*t = v, thus

L = v*t0 + v*t/2 = (t0 + t/2)*v

Nishan26.08.14, 06:30why must the t=4s divide 2 ???

## Leave a comment