# Answer to Question #15009 in Mechanics | Relativity for Patricia Hendricksen

Question #15009

A rotten tomato is thrown with an initial velocity of 15 m/s at an angle of 45. Where on stage does it land?

Expert's answer

Let's find the time of the flight of a tomato.

T = 2(15[m/s]*cos(π/4)/9.8[m/s²]) ≈ 2.1646 [s].

So, the tomato will cover the distance

D ≈ 15[m/s]*sin(π/4)*2.1646[s] = 22.9591 [m].

T = 2(15[m/s]*cos(π/4)/9.8[m/s²]) ≈ 2.1646 [s].

So, the tomato will cover the distance

D ≈ 15[m/s]*sin(π/4)*2.1646[s] = 22.9591 [m].

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