# Answer to Question #1357 in Mechanics | Relativity for Jon ALlen

Question #1357

A block of unknown mass is attached to a

spring of spring constant 9.6 N/m and undergoes simple harmonic motion with an amplitude of 14.8 cm. When the mass is halfway

between its equilibrium position and the end-point, its speed is measured to be 32.7 cm/s.

Calculate the mass of the block.

Answer in units of kg.

spring of spring constant 9.6 N/m and undergoes simple harmonic motion with an amplitude of 14.8 cm. When the mass is halfway

between its equilibrium position and the end-point, its speed is measured to be 32.7 cm/s.

Calculate the mass of the block.

Answer in units of kg.

Expert's answer

We can use the law of enegry conservation:

kx

where

k = 9.6 N/m, x1 = 14.8 x 10

so

m = k(x

kx

_{1}^{2}/2 = kx_{2}^{2}/2+ mv^{2}/2where

k = 9.6 N/m, x1 = 14.8 x 10

^{-2}m , x2 = 7.4 x 10^{-2}m, v = 32.7x10^{-2}m/s^{2};so

m = k(x

_{1}^{2}-x_{2}^{2})/v^{2}= 9.6 (14.8^{2}- 7.4^{2})/32.7^{2}= 1.47 kg.Need a fast expert's response?

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